Сначала найдем значение переменной а:
а = √2(1/2048)2^(1/2048)2(1/2048) = 2^1/(2048∗2)1/(2048*2)1/(2048∗2) = 2^1/40961/40961/4096
Теперь найдем сумму a + a:
a + a = 2 a = 2 2^1/40961/40961/4096 = 2^1/4096+11/4096 + 11/4096+1 = 2^1/4096+4096/40961/4096 + 4096/40961/4096+4096/4096 = 2^4097/40964097/40964097/4096 = 2^1+1/40961 + 1/40961+1/4096 = 2
Итак, сумма a + a равна 2.
Сначала найдем значение переменной а:
а = √2(1/2048)2^(1/2048)2(1/2048) = 2^1/(2048∗2)1/(2048*2)1/(2048∗2) = 2^1/40961/40961/4096
Теперь найдем сумму a + a:
a + a = 2 a = 2 2^1/40961/40961/4096 = 2^1/4096+11/4096 + 11/4096+1 = 2^1/4096+4096/40961/4096 + 4096/40961/4096+4096/4096 = 2^4097/40964097/40964097/4096 = 2^1+1/40961 + 1/40961+1/4096 = 2
Итак, сумма a + a равна 2.