To find the force (F), we can use Newton's second law which states that force is equal to the mass times the acceleration.
Given:
First, we need to calculate the acceleration (a) using the formula:a = (Vf^2 -V0^2)/ (2*l)
Given that the final velocity (Vf) is 0 (since it comes to stop), the formula becomes:a = (0 - 13^2) / (2*2.9)a = -169 / 5.8a ≈ -29.14 m/s^2
Now, we can calculate the force using Newton's second law: F = maF = 7 kg -29.14 m/s^2F ≈ -203.98 N
Therefore, the force exerted on the object is approximately 203.98 N in the direction opposite to its initial motion.
To find the force (F), we can use Newton's second law which states that force is equal to the mass times the acceleration.
Given:
Mass (m) = 7 kgLength (l) = 2.9 mInitial velocity (V0) = 13 m/sFirst, we need to calculate the acceleration (a) using the formula:
a = (Vf^2 -V0^2)/ (2*l)
Given that the final velocity (Vf) is 0 (since it comes to stop), the formula becomes:
a = (0 - 13^2) / (2*2.9)
a = -169 / 5.8
a ≈ -29.14 m/s^2
Now, we can calculate the force using Newton's second law: F = ma
F = 7 kg -29.14 m/s^2
F ≈ -203.98 N
Therefore, the force exerted on the object is approximately 203.98 N in the direction opposite to its initial motion.