To find sinB and tgB, we can use the Pythagorean identity sin^2(B) + cos^2(B) = 1 and the definition of tangent as the ratio of sine and cosine.
Given that CosB = 15/17, we can find sinB as follows:sin^2(B) + (15/17)^2 = 1sin^2(B) + 225/289 = 1sin^2(B) = 1 - 225/289sin^2(B) = 64/289sinB = ±√(64/289) = ±8/17
Since B is an angle in the first or fourth quadrant (because CosB is positive), sinB is positive.Therefore, sinB = 8/17.
To find tgB, we use the definition of tangent:tgB = sinB / CosBtgB = (8/17) / (15/17)tgB = 8/15
To find sinB and tgB, we can use the Pythagorean identity sin^2(B) + cos^2(B) = 1 and the definition of tangent as the ratio of sine and cosine.
Given that CosB = 15/17, we can find sinB as follows:
sin^2(B) + (15/17)^2 = 1
sin^2(B) + 225/289 = 1
sin^2(B) = 1 - 225/289
sin^2(B) = 64/289
sinB = ±√(64/289) = ±8/17
Since B is an angle in the first or fourth quadrant (because CosB is positive), sinB is positive.
Therefore, sinB = 8/17.
To find tgB, we use the definition of tangent:
tgB = sinB / CosB
tgB = (8/17) / (15/17)
tgB = 8/15