AB = AC sin(B) = CD sin(C) = 3 sin(45°) = 3 √2 / 2 = 3√2 / 2
Therefore, the length of segment AB is 3√2 / 2 units.
AB = AC sin(B) = CD sin(C) = 3 sin(45°) = 3 √2 / 2 = 3√2 / 2
Therefore, the length of segment AB is 3√2 / 2 units.