To solve the first equation, we need to expand it first:
х^2 - 2х = 63

Next, we move all terms to one side of the equation to set it equal to zero:
х^2 - 2х - 63 = 0

Now, we can factor this quadratic equation:
(х - 9)(х + 7) = 0

This means that х could be either 9 or -7.

To solve the second equation, we need to expand it first:
х^2 + 4х = 77

Next, we move all terms to one side of the equation to set it equal to zero:
х^2 + 4х - 77 = 0

Now, we can factor this quadratic equation:
(х - 7)(х + 11) = 0

This means that х could be either 7 or -11.

Therefore, the solutions to the equations are х = 9, х = -7, х = 7, and х = -11.