To find the roots of this equation, we can expand the expression:

2x³ + 3x²y² - 6x²y = 0

Now we can factor out x:

x(2x² + 3xy² - 6xy) = 0

Now we can factor further:

x(2x² + 3xy - 6y) = 0

Setting each factor to zero:

x = 0

2x² + 3xy - 6y = 0

Now we can solve for x in the second equation:

2x² + 3xy - 6y = 0
x(2x + 3y) - 6y = 0
x = (6y)/(2x + 3y)

So the roots of the equation are x = 0 and x = (6y)/(2x + 3y) when the expression is equal to zero.