1) y=3x^2y' = 6xy'(1) = 6(1) = 6
Ответ: y'(1) = 6
2) y = cosxy' = -sinxy'(π/6) = -sin(π/6) = -1/2
Ответ: y'(π/6) = -1/2
3) y = -2sinxy' = -2cosxy'(π/4) = -2cos(π/4) = -2/√2 = -√2
Ответ: y'(π/4) = -√2
4) y = 2 + √xy' = 1/(2√x)y'(4) = 1/(2√4) = 1/4
Ответ: y'(4) = 1/4
1) y=3x^2
y' = 6x
y'(1) = 6(1) = 6
Ответ: y'(1) = 6
2) y = cosx
y' = -sinx
y'(π/6) = -sin(π/6) = -1/2
Ответ: y'(π/6) = -1/2
3) y = -2sinx
y' = -2cosx
y'(π/4) = -2cos(π/4) = -2/√2 = -√2
Ответ: y'(π/4) = -√2
4) y = 2 + √x
y' = 1/(2√x)
y'(4) = 1/(2√4) = 1/4
Ответ: y'(4) = 1/4