Im: The maximum value of the sine function is 1, so Im = 5 Ip: The peak value of the current waveform is the same as the maximum value, so Ip = 5 D: The amplitude of the sine function is 5, so D = 5 T: The time period of the waveform is given by T = 2π/200 = 1/100 seconds
The given equation is I = 5sin(200πt)
Im: The maximum value of the sine function is 1, so Im = 5
Ip: The peak value of the current waveform is the same as the maximum value, so Ip = 5
D: The amplitude of the sine function is 5, so D = 5
T: The time period of the waveform is given by T = 2π/200 = 1/100 seconds